how to do extraneous solutions

Extraneous solutions (video) Equations Khan Academy. WebSo this is an extraneous solution. They key here is that we multiplied both sides by a variable expression. In this case, we multiplied both sides by x minus one. You can do that. You can multiply both sides by a variable expression, and it is a legitimate algebraic.

Extraneous solutions (video) Equations Khan Academy
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Web  Generally, the best way to find extraneous solutions is to solve the equation and find values for the variables. Then, check your answers by substituting the values.

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